Two-time defending champion Aryna Sabalenka of Belarus owns the longest Australian Open women’s singles winning streak in more than a decade after advancing out of the third round on Friday in Melbourne.
Sabalenka got past Denmark’s Clara Tauson 7-6 (5), 6-4 in 2 hours, 6 minutes.
The victory was the 17th in a row for Sabalenka at the event. The last woman with a longer streak was another Belarusian, Victoria Azarenka, who won 18 in a row from 2012 to 2014, capturing the title in the first two of those years.
Sabalenka emerged with more winners (39-26) and fewer unforced errors (33-25) than Tauson in a match that featured 11 service breaks — including each of the first seven games.
Sabalenka failed to take advantage of four set points at 5-6 in the first set before prevailing in a tiebreaker. Tauson lost her serve early in the second set, then fought back to a 4-4 tie before Sabalenka took the final two games.
Tauson is ranked 42nd in the world but has never reached a Grand Slam quarterfinal.
“She put me under pressure,” Sabalenka said. “She played really great tennis under pressure, as well. It was great level from her. If she’s going to continue working, improving herself, playing the way she played today, of course, she’s going to be there (at the highest level).”
In other Friday action, No. 18 Donna Vekic of Croatia outlasted No. 12 Diana Shnaider of Russia 7-6 (4), 6-7 (3), 7-5. No. 11 Paula Badosa of Spain downed No. 17 Marta Kostyuk of Ukraine 6-4, 4-6, 6-3, and No. 27 Anastasia Pavlyuchenkova of Russia routed Germany’s Laura Siegemund 6-1, 6-2.
The later Friday slate was due to include No. 7 Jessica Pegula of the United States against Serbia’s Olga Danilovic, No. 3 Coco Gauff of the United States against No. 30 Leylah Fernandez of Canada, and four-time Grand Slam champion Naomi Osaka of Japan against Switzerland’s Belinda Bencic.
–Field Level Media
